Nilai Lim
X-0
1 - COS² 2x per 3 Sinx tan 4x
Jawaban:
[tex]lim \: \frac{1 - { \cos }^{2}(2x) }{3sin(x)tan(4x) } [/tex]
[tex] = lim \: \frac{1 - (1 - { sin }^{2}(2x)) }{3sin(x)tan(4x) } [/tex]
[tex] = lim \: \frac{{ sin }^{2}(2x) }{3sin(x)tan(4x) } \times \frac{ \frac{1}{ {x}^{2} } }{ \frac{1}{ {x}^{2} } } [/tex]
[tex] = lim \: \frac{ (\frac{sin(2x)}{x})^{2} }{3 \frac{sin(x)}{x} \times \frac{tan(4x)}{x} } [/tex]
[tex] = \frac{ {2}^{2} }{3 \times 1 \times 4} [/tex]
[tex] = \frac{1}{3} [/tex]
[answer.2.content]
